WebOct 24, 2024 · The balanced equation tells us that 13 moles of O2 are needed for every 2 moles of butane. If you have 0.09 moles of butane [thanks for doing that calculation], you need to multiply that by the molar ratio (13 moles O2/2 moles butane). So 0.09 x … WebAug 25, 2024 · Alkanes (the most basic of all organic compounds) undergo very few reactions. The two reactions of more importaces is combustion and halogenation, (i.e., substitution of a single hydrogen on the alkane for a single halogen) to form a haloalkane. The halogen reaction is very important in organic chemistry because it opens a gateway …
How to Balance C4H10 + O2 = CO2 + H2O: (Butane …
WebThe balanced chemical equation for the reaction between butane (C4H10) and oxygen is: 2 C4H10 ( g ) + 13 O2 ( g ) 8 CO2 ( g ) + 10 H2O ( g ) We can interpret This problem has been solved! You'll get a detailed solution from a … WebGiven the balanced equation for the reaction of butane and oxygen: 2C4H10 + 1302 + 8CO2 + 10H2O + energy How many moles of oxygen gas are required in the combustion of 5 moles of butane? A) 20. mol C) 40. mol B) 10. … dorcas fashion
The combustion of butane in oxygen produces carbon dioxide and …
WebApr 6, 2024 · The given equation to be balanced is C4H 10 +O2 → CO2 +H 2O. We begin by counting the number of C atoms on both sides. We have 4C on the left and 1C on the … WebOct 21, 2024 · 116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide. Next, we shall determine the limiting reactant. This can be obtained as follow: From the balanced equation above, 116 g of butane reacted with 416 g of oxygen. Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen. WebButane burns completely in oxygen according to the equation 2C4H10 plus 13O2 reacting to give 8CO2 plus 10H2O. If 44 grams of carbon dioxide is produced in this reaction, how much oxygen is consumed? In this question, we have butane, C4H10, which is a … dorcan school swindon